b^2=b+110

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Solution for b^2=b+110 equation:


Simplifying
b2 = b + 110

Reorder the terms:
b2 = 110 + b

Solving
b2 = 110 + b

Solving for variable 'b'.

Reorder the terms:
-110 + -1b + b2 = 110 + b + -110 + -1b

Reorder the terms:
-110 + -1b + b2 = 110 + -110 + b + -1b

Combine like terms: 110 + -110 = 0
-110 + -1b + b2 = 0 + b + -1b
-110 + -1b + b2 = b + -1b

Combine like terms: b + -1b = 0
-110 + -1b + b2 = 0

Factor a trinomial.
(-10 + -1b)(11 + -1b) = 0

Subproblem 1

Set the factor '(-10 + -1b)' equal to zero and attempt to solve: Simplifying -10 + -1b = 0 Solving -10 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '10' to each side of the equation. -10 + 10 + -1b = 0 + 10 Combine like terms: -10 + 10 = 0 0 + -1b = 0 + 10 -1b = 0 + 10 Combine like terms: 0 + 10 = 10 -1b = 10 Divide each side by '-1'. b = -10 Simplifying b = -10

Subproblem 2

Set the factor '(11 + -1b)' equal to zero and attempt to solve: Simplifying 11 + -1b = 0 Solving 11 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-11' to each side of the equation. 11 + -11 + -1b = 0 + -11 Combine like terms: 11 + -11 = 0 0 + -1b = 0 + -11 -1b = 0 + -11 Combine like terms: 0 + -11 = -11 -1b = -11 Divide each side by '-1'. b = 11 Simplifying b = 11

Solution

b = {-10, 11}

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